4^3x-2=(1/8)^2x-1

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Solution for 4^3x-2=(1/8)^2x-1 equation: 



4^3x-2=(1/8)^2x-1

We move all terms to the left:

4^3x-2-((1/8)^2x-1)=0



Domain of the equation: 8)^2x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4^3x-((+1/8)^2x-1)-2=0

We multiply all the terms by the denominator


4^3x*8)^2x-1)-((-2*8)^2x-1)+1=0

We add all the numbers together, and all the variables

4^3x*8)^2x-1)-((-16)^2x-1)+1=0

Wy multiply elements

32x^4-16)^2x-1)+1=0

We do not support expression: x^4

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